1. Find the kinetic energy of a .023 kg bullet moving at 420 m/s.

Question

asked Mar 20, 2021 141k views

1 Answer

Alex Dunae · Answer 1 · 2021-03-25T20:50:18+0000

Answer:

Correct answer: Ek = 2,028.6 J

Step-by-step explanation:

Ek = m v²/2 = 0.023 · 220² = 0.023 · 176,400/2 = 2,028.6 J

God is with you!!!