Question

Find the average value of the function on the given interval.
f(x)=2-3x^2; [1,3]

Answer 1

F(1)=2-3×1^2=-1

F(2)=2-3×2^2=-10

F(3)=2-3×3^2=-25

The average will be summer/6

Average=-36/6

Average=-6