Question

Find the average value of f(x) = √x+1 over the interval [0, 8].

Answer 1

The average value of
`f(x)` over [0, 8] is

`\displaystyle\frac1{8-0}\int_0^8√(x+1)\,\mathrm dx=\frac1{12}(x+1)^(3/2)\bigg|_0^8=\frac{13}6`