Question

A 0.650 kg air-track glider is attached to each end of the track by two coil springs. It takes a horizontal force of 0.900 N to displace the glider to a new equilibrium position, x= 0.070 m. Find the effective spring constant of the system.

Answer 1

Spring constant will be 12.857 N/m

Step-by-step explanation:

Horizontal force is given F = 0.900 N

Displaced in position x = 0.070 m

We have to fond the spring constant

Displacing force is equal to
`F=Kx`, here K i spring constant

So spring constant
`K=(F)/(x)=(0.900)/(0.070)=12.857N/m`

So effective spring constant will be 12.85 N /m