Question

suppose the length of a rectangle is one more than its width, and has an area of 60 ft squared. find the dimensions of the rectangle to the nearest hundreth

Answer 1

• width: 7.26 ft
• length: 8.26 ft

Explanation:

Let w represent the width of the rectangle. Then w+1 is the length, and the area is ...

w(w+1) = 60

w^2 +w + 0.25 = 60.25 . . . . eliminate parentheses, complete the square

(w +0.5)² = 60.25

w +0.5 = √60.25

w = -0.5 +√60.25 ≈ 7.26 . . . . . feet

w+1 = 8.26 . . . . feet = length

The dimensions of the rectangle are 7.26 feet by 8.26 feet.