Question

If you mix 100 milliliters of 10 degrees Celsius of water and 100 milliliters of 90 degrees celsius of water what will be your final temperature of the mixture

Answer 1

Final temperature of the mixture is 50°C

Step-by-step explanation:

This is a typical calorimetry problem, where the heat yielded by a compound is immediately won by another.

Water at 90°C raise the temperature of water at 10°

Density of water = 1g/mL

Mass of water = 100 g, because the volume is 100mL

If the two pieces of water are in a calorimeter where heat is not released or gained, the sum of both heats is 0

4.18 J/g°C . 100 g ( T°final - 90°C) + 4.18 J/g°C . 100 g ( T°final - 10°C) = 0

418 J/°C T°final - 37620 J + 418 J/°C T°final - 4180J = 0

836 J/°C T°final - 37620J - 4180J = 0

836 J/°C T°final = 41800J

T°final = 41800J / 836 °C/J = 50°C

Answer 2

Final temperature of the mixture is 50°C

Step-by-step explanation:

This is a typical calorimetry problem, where the heat yielded by a compound is immediately won by another.

Water at 90°C raise the temperature of water at 10°

Density of water = 1g/mL

Mass of water = 100 g, because the volume is 100mL

If the two pieces of water are in a calorimeter where heat is not released or gained, the sum of both heats is 0

4.18 J/g°C . 100 g ( T°final - 90°C) + 4.18 J/g°C . 100 g ( T°final - 10°C) = 0

418 J/°C T°final - 37620 J + 418 J/°C T°final - 4180J = 0

836 J/°C T°final - 37620J - 4180J = 0

836 J/°C T°final = 41800J

T°final = 41800J / 836 °C/J = 50°C