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2 votes
What is the surface area of the rectangular pyramid below?

A rectangular pyramid. The rectangular base has a length of 4.8 meters and height of 3.8 meters. 2 triangular sides have a base of 4.8 meters and height of 2.6 meters. 2 triangular sides have a base of 3.8 meters and height of 2.9 meters.

asked
User Vereb
by
7.2k points

2 Answers

2 votes

Answer:

Step-by-step explanation:The area of the base is 24 cm2.

There are four lateral faces.

The total surface area of the figure is 66.4 cm2.

i just did the test

answered
User Rutix
by
8.1k points
4 votes

Answer:


SA=41.74\ m^2

Explanation:

we know that

The surface area of the rectangular pyramid is equal to the area of its rectangular base plus the area of its four triangular faces

so

step 1

Find the area of its rectangular base


A=(4.8)(3.8)


A=18.24\ m^2

step 2

Find the area of its four triangular faces


A=2[(1)/(2)(4.8)(2.6)]+2[(1)/(2)(3.8)(2.9)]


A=12.48+11.02=23.5\ m^2

step 3

Find the surface area

Adds the areas


SA=18.24+23.5


SA=41.74\ m^2

answered
User Recvec
by
8.5k points

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