Question

A train traveling at 60 miles per hour reaches a tunnel. The front of the train enters the tunnel, and 40 seconds later the front of the train exits the tunnel. How many feet are in the length of the tunnel?

Answer 1

Distance covered in 40 sec must be equal to length of train which is equal to 3520 feet.

Explanation:

Speed of train = 60 mph = 88 feet/sec

Total time taken by front of train in travelling the tunnel = 40 sec

Length of train = s =?

Distance covered in 40 sec must be equal to length of train. So,

`v=(s)/(t)\\\\s=v* t\\\\s=88 * 40\\\\s=3520 feet`