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Solve, 3y(4y−1)−2y(6y−5)=9y−8(3+y)

Solve, 3y(4y−1)−2y(6y−5)=9y−8(3+y)
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Solve, 3y(4y−1)−2y(6y−5)=9y−8(3+y)

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User Gregory Bell
by
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1 Answer

6 votes

Answer:

3y(4y-1)-2y(6y-5)=9y-8(3+y)

12y∧2-3y-12y∧2+10y=9y-24-8y

12y∧2-12y∧2-3y+10y=9y-8y-24

7y=y-24

7y-y=-24

6y=-24

y=-24/6=-4

Explanation:

answered
User Mesutpiskin
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8.0k points
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