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Vertex form of -x^2-8x-16

Vertex form of -x^2-8x-16
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4 votes
Vertex form of -x^2-8x-16

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User Stenehall
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7.7k points

1 Answer

5 votes

Answer:


y = - (x + 4)^(2)

answered
User Piwo
by
7.4k points
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