Question

Given cos0 = -2/3 and lies in quadrant lll what is the exact value of sin 0 in simplified form ?

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Answer 1

sin(θ) = -(√5)/3

Explanation:

In quadrant III, both sine and cosine are negative. Then the value of interest is ...

sin(θ) = -√(1 - cos(θ)²) = -√(1 -4/9)

sin(θ) = -(√5)/3