Question

Carol drops a stone in a mine shaft 122.5 metres deep.How

soonafter she drops the stone does she hear it hit the bottom of
theshaft?

Answer 1

T = 5.36 s

Step-by-step explanation:

given,

depth of the mine shaft = 122.5 m

speed of the sound = 340 m/s

time taken = ?

time taken by the stone to reach at the bottom

using equation of motion

`s = u t + (1)/(2)gt^2`

initial speed , u = 0 m/s

`t = \sqrt{(2s)/(g)}`

`t = \sqrt{(2* 122.5)/(9.8)}`

t = 5 s

time taken by the sound to travel

d =v x t

`t = (d)/(v)`

`t = (122.5)/(340)`

t = 0.36 s

total time taken for the sound to reach carol after dropping the stone

T = 5 + 0.36

T = 5.36 s