Question

2. Sketch graphs of the following equations.

a. x^2+y^2+10x−4y+33=0
b. x^2+y^2+14x−16y+104=0
c. x^2+y^2+4x−10y+29=0

Answer 1

Look at the attachment.

Explanation:

a)
`x^2+y^2+10x-4y+33=0\\x^2+10x+29=4y-y^2-4\\(y-2)^2=-x^2-10x-29\\y=2-√(-x^2-10x-29)`

b)
`x^2+y^2+14x-16y+104=0\\x^2+14x+104=16y-y^2\\(y-8)^2=-x^2-14x-40\\y=8-√(-x^2-14x-40)`

c)
`x^2+y^2+4x-10y+29=0\\x^2+4x+29=10y-y^2\\(y-5)^2=-x^2-4x-4\\y=5-√(-x^2-4x-4)`

Graphs are added in the attachment.