Question

In a diffraction experiment, light of 600nm wavelengthproduces

a first-order maximum 0.350 mm from the central maximum ona distant
screen. A second monochromatic source produces athird-order maximum
0.870 mm from the central maximum when itpasses through the same
diffraction grating. What is thewavelength of the light from the
second source?

Answer 1

λ≅
`4.97*10^(-4)nm`

λ≅497 nm

Step-by-step explanation:

In order to find the wavelength of the light from the second source we are going follow the following procedure.

Formula:

Nλ=d*x/l

Where:

N is the order of maximum

λ is the wavelength

d is the distance from central maximum

x/l is the ratio

For first monochromatic source:

We will find the ratio x/l.

`(x)/(l)`=Nλ/d

`(x)/(l)=(1*600*10^-^6)/(0.350*10^-^3)`

`(x)/(l)=1.71428`

For second monochromatic source:

Nλ=d*x/l

λ=
`(d*x/l)/(N)`

λ=
`(0.870*10^-^3*1.71428)/(3)`

λ≅
`4.97*10^(-4)nm`

λ≅497 nm