Question

during this reaction, p4+502 p4010 0.800 moles of product was made in 30 sec. what is the rate of reaction​

Answer 1

Rate of reaction is : 0.027 mol/Ls.

Step-by-step explanation:

`P_(4) + 5 O_(2) \rightarrow P_(4)O_(10)`

`rate = +(1)/(1)(\Delta [P_(4)O_(10)])/(\Delta t)`

`{\Delta t} = 30 sec`

`\Delta [P_(4)O_(10)] = 0.8`

`rate = +(1)/(1)(0.8)/(30)`

rate = 0.027 mol/Ls

`rate = 0.027 moleL^(-1)s^(-1)`