Question

What is an equation of the line that passes through (0, 8) and (4, 0)?

A. y = -2 x + 8
B. y = -2 x + 4
C. y = 2 x + 8
D. y = 2 x + 4

Answer 1

The answer would be y = -2x + 8

Answer 2

Explanation:

first thing we do is find the slope by using ur 2 points and the slope formula

slope = (y2 - y1) / (x2 - x1)

(0,8)...x1 = 0 and y1 = 8

(4,0)...x2 = 4 and y2 = 0

now we sub

slope = (0 - 8) / (4 - 0) = -8/4 = -2

so we have a slope of -2

now we use y = mx + b and either one of ur points...m represents the slope

y = mx + b

slope(m) = -2

(0,8)....x = 0 and y = 8

now sub...we are looking for b, the y int

8 = -2(0) + b

8 = 0 + b

8 = b

so ur equation is : y = -2x + 8 <===

u can check this by subbing in either of ur points into ur equation to see if its true.