Register

Empirical formula of 97.56 carbon, 4.878 hydrogen, 52.03 oxygen, and 45.53 nitrogen

Empirical formula of 97.56 carbon, 4.878 hydrogen, 52.03 oxygen, and 45.53 nitrogen
asked 227k views
2 votes
Empirical formula of 97.56 carbon, 4.878 hydrogen, 52.03 oxygen, and 45.53 nitrogen

asked
User DSav
by
7.9k points

1 Answer

6 votes

Answer:

The formula is in the attached file

Step-by-step explanation:

Empirical formula of 97.56 carbon, 4.878 hydrogen, 52.03 oxygen, and 45.53 nitrogen-example-1
answered
User Gleitonfranco
by
8.4k points
← Prev Question Next Question →

Related questions

User Hesam Rasoulian
asked Nov 26, 2024 212k views
Three acres equals how many square feet? a. 43,560 b. 130,680 c. 156,840 d. 27,878,400
Hesam Rasoulian asked Nov 26, 2024
by Hesam Rasoulian
8.1k points
1 answer
4 votes
212k views
Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

Compare and contrast an electric generator and a battery??
How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
Can someone complete the chemical reactions, or write which one do not occur, and provide tehir types? *c2h4+h2o *c3h8 + hcl *c2h2+br2 *c4h10+br2 *c3h6+br2
Link Copied!