Question

Assume that the car at point A and the one at point E are traveling along circular paths that have the same radius. If the car at point A now moves twice as fast as the car at point E, how is the magnitude of its acceleration related to that of car E. Assuming that all cars have equal speeds, which car has the acceleration of the greatest magnitude, and which one has the acceleration of the least magnitude? Let be the velocity of the car at point D. What can you say about the acceleration of the car at that point

Answer 1

Step-by-step explanation:

Given

Car at point A and E are travelling along circular path with same radius

Car at point A has twice the velocity of car at Point B

Assuming the magnitude of velocity constant

Let r be the radius of circle and v the be velocity of car at point B

there will only be centripetal acceleration and no tangential acceleration

`a_c=(v^2)/(r)`

at Point A

`(a_c)_A=((2v)^2)/(r)`

`(a_c)_A=(4v^2)/(r)`

`(a_c)_B=(v^2)/(r)`

so the magnitude of acceleration of car at point A is more than magnitude of car at Point B