Question

Two parallel electrodes that are typically separated by 3cm with a 5V potential difference across them.What is the magnitude of the electric field between the two electrodes in ionization type detectors?

Answer 1

166.67 N/C

Step-by-step explanation:

Potential difference between a plate equals the product of the electric field and the distance between the plates

Δv = Ed

E = Δv / d = 5 / 0.03 since 3 cm = 0.03 m

E = 166.67 V/m = 166.67 N/C