Question

X+7y=0 2x-8y=22 with substitution

Answer 1

For this case we have the following system of equations:

`x + 7y = 0\\2x-8y = 22`

According to the first equation we have:

`x = -7y`

Thus, we have the equivalent system:

`x = -7y\\2x-8y = 22`

Substituting the first equation in the second equation we have:

`2 (-7y) -8y = 22\\-14y-8y = 22`

Equal signs are added and the same sign is placed:

`-22y = 22\\y = \frac {22} {- 22}\\y = -1`

We look for the value of the variable x:

`x = -7y\\x = -7 (-1)\\x = 7`

Thus, the system solution is:
`(x, y) :( 7, -1)`

Answer:

`(x, y) :( 7, -1)`