Answer: B
Explanation:
α/360r²π=area BOC(part of circle with radius 6√2)
Area of triangle CDO= (r²/4√3)/2
Area of shaded region= Area of BOC-Area of triangle CDO
Area of shaded region=α/360r²π-r²/8√3
α=∡BOC=60
r=6√2
Area of shaded region=60/360*72π-72/8*√3=12π-9√3