How many grams of sucrose would you add to water to make a total of 2.1 L of 9 % solution (mass per volume)? Make your answer's precision to one decimal place.

Question

asked Sep 26, 2021 173k views

1 Answer

Jarrodparkes · Answer 1 · 2021-10-03T04:16:32+0000

Answer : The mass of sucrose added to water will be, 189.0 grams.

Explanation :

As we are given that 9 % solution (mass per volume) that means 9 grams of sucrose present in 100 mL volume of solution.

Total given volume of solution = 2.1 L = 2100 mL (1 L = 1000 mL)

Now we have to determine the mass of sucrose in solution.

As, 100 mL of solution contains 9 grams of sucrose

So, 2100 mL of solution contains
(2100mL)/(100mL)* 9g=189.0 grams of sucrose

Therefore, the mass of sucrose added to water will be, 189.0 grams.