Question

According to this decay series chart, which is the proper order of nuclear particle emission that occurs during the transition from lead-214 to lLead-210?

A) Lead-214 changes to bismuth-214.
B) Bismuth-214 changes to polonium-214.
C) Polonium-214 changes to lead-210.

Answer 1

Step-by-step explanation:

An alpha particles is basically a helium nucleus and it contains 2 protons and 2 neutrons.

Symbol of an alpha particle is
`^(4)_(2)\alpha`.

A beta particle is a particle with a negatively charged electron. Symbol of a beta particle is
`^(0)_(-1)\beta`.

According to the given question, the decay series chart along with reaction equation are as follows.

(a) Lead-214 changes to bismuth-214.

`^(214)_(82)Pb \rightarrow ^(214)_(83)Bi + ^(0)_(-1)e`

(b) Bismuth-214 changes to polonium-214.

`^(214)_(83)Bi \rightarrow ^(214)_(84)Po + ^(0)_(-1)e`

(c) Polonium-214 changes to lead-210.

`^(214)_(84)Po \rightarrow ^(210)_(82) + ^(4)_(2)He`

Therefore, we can conclude that proper order of nuclear particle emission is beta, beta, alpha.