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You are interested in two traits in rabbits, each of which is controlled by a separate gene with two alleles:

a) coat color (brown, B, is completely dominant to white,

b) and tail (tailed, T, is completely dominant to tail-less,

c) You cross a brown, tailed rabbit that is heterozygous at both loci with a white, tail-less rabbit and produce a large number of offspring.

Among the offspring you find only two phenotypes in equal proportions: brown, tailed and white, tail-less.

1 Answer

2 votes

Answer:the scenario here with the brown tailed rabbit RrTt

The white tailess rabbit is rt.

Crossing both yields the below offsprings possibilities;

For colour: Rr or rr

For tail: Tt or tt

That means they would produce equal numbers of Brown tailed & white tailess rabbits.

Step-by-step explanation:

answered
User Srilakshmi
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