Question

What is the average rate of change of the function on the interval from x = 0 to x = 5?

f(x)=

1/2^(3)x

Answer 1

Average rate of change
`=(1)/(8)`

Explanation:

Given interval are from
`x=0\ to\ x=5`

Also,
`=(1)/(2^3)x=(1)/(8)x`

Average rate of change
`=(f(b)-f(a))/(b-a)\ for\ given\ interval\ [a,b]`

Here given intervals are
`a=0\ and\ b=5`

Plugging these value in formula, we get.

Average rate of change
`=((1)/(8)(5)-(1)/(8)(0))/(5-0)\\\\=((1)/(8)(5)-0)/(5-0)\\ \\=((1)/(8)(5))/(5)\\\\=(1)/(8)`