Question

select the best explanation for why methanol, ch3oh, cannot be used as a solvent for the deprotonation of a terminal alkyne by sodium amide, nanh2.

Answer 1

d. Methanol is more acidic than the alkyne and will be deprotonated instead.

Step-by-step explanation:

because acidity is the ability to lose H+, leaving an anion behind; acidity depends on the stability of the anion.