Question

E=4i+3j A=5i finfd E.A=EAcos

Answer 1

theta = 36.87

Explanation:

E.A= (4i+3j).5i= 20

|E| |A| =

`| e| |a| = \sqrt{4 ^(2) + {3}^(2) } * 5 = 25`

`\cos(theta) = (e.a)/( |e ||a | ) = (20)/(25) = (4)/(5) \\ theta = \cos ^( - 1) ( {.8} ) = 36.87`