Question

if the zeros of a quadratic function are -4 and 6, what is the equation of the axis of symmetry of F?

Answer 1

Answer: x = 1

Explanation:

`\mathrm{The \ quadratic \ equation \ with \ roots \ at \ -4 \ and \ 6 \ is \ given \ by:}\\$$\begin{aligned}&y=(x+4)(x-6) \\&y=xx+x\left(-6\right)+4x+4\left(-6\right) \\&y=x^2-2x-24\end{aligned}$$`

`\mathrm{For \ a \ quadratic \ equation \ in \ standard-form \ $y=ax^(2)+b x+c$.}\\The axis of symmetry is a vertical line $ x=(-b)/(2 a) . \\ \marthm{Here } \ b & =-2 \quad, \ a=1\end{array}$`

`x=(-(-2))/(2 * 1)=(2)/(2)=1 \\\\ \mathrm{Therefore \ x=1 \ is \ the \ equation \ of \ the \ axis \ of \ symmetry \ of \ F}`