Question

a rocket traveling at 95 m/s accelerates uniformly to 155 m/s in 5 seconds. What is its acceleration?

Answer 1

12m/s.s

Explanation:

Acceleration =change velocity /time

Acceleration =155m/s-95m/s ÷ 5s

Acceleration =60m/s÷5s

Acceleration =12m/s.s

Answer 2

See below:

Explanation:

Hello! My name is Galaxy and I will be helping you today. I hope you are having a nice day!

We can solve this problem using a single formula, that is:
`(V_(f)-V_(i) )/(T)`. This formula is used to solve for acceleration between two velocities during a certain amount of time. We can use this formula to solve our problem.

In this case, the Final Velocity is 155 m/s and the Initial Velocity is 95 m/s in 5 seconds.

We can use this information to create/fill in our formula.

`(155-95(m)/(s) )/(5 seconds)=(60(m)/(s))/(5seconds)=12(m)/(s^2)`

We can do this due to simplification and basic theory.

We know that if we divide meters per second by seconds, we get meters per second per second.

Due to this, our formula works, and we get the Acceleration as 12 meters per second squared or 12 meters per second per second.

Cheers!