Question

the lenght of a rectangle is twice its breadth. if the perimeter is 72 meter, find the lenght and breadth of the rectangle

Answer 1

Given :

• The length of a rectangle is twice its breadth and it's perimeter is 72 m, We are to find the length and breadth of the rectangle.

`\:`

Solution :

Let's assume the breadth of the rectangle as x then the length will become 2x.

We know that,

• Perimeter = 2( length + breadth)

So,

According to the Question :

⇢ 72 = 2( 2x + x)

⇢ 72 = 2(3x)

⇢ 72 = 6x

⇢ 6x = 72

⇢ x = 72/6

⇢ x = 12

Hence,

• Breadth = 12m
• Length = 2(12)m = 24m

Answer 2

• Let the breadth of rectangle be x.Thus, the length will be 2x.And we given – Perimeter is 72 meter.

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`\qquad`
`\pink{\bf \longrightarrow Perimeter _((Rectangular) ) = 2( Length + Breadth) }`

`\qquad`
`\sf \longrightarrow 72 = 2( 2x + x)`

`\qquad`
`\sf \longrightarrow 72 = 6x`

`\qquad`
`\sf \longrightarrow x =\cancel{(72)/(6)}`

`\qquad`
`\pink{\bf\longrightarrow x = 12 \: m}`

• Breadth of rectangle is 12 m.

We know that, value of x is '12'. Therefore, we'll substitute the value of x in given Length 2x to find out the Length. Therefore —

⠀

`\qquad`
`\twoheadrightarrow\sf Length = \Big\{2x \Big\}\\\\`

`\qquad`
`\twoheadrightarrow\sf Length = 2 * 12\\\\`

`\qquad`
`\purple{\twoheadrightarrow{\pmb{\sf{Length = 24\;m}}}}\\\\`

• Hence, length will be 24 m.

`\rule{250px}{.2ex}\\`

More To know :-

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`\sf Area _((Rectangle) )= \bf{Length * Breadth}`

☀️
`\sf Diagonal_((Rectangle)) = \bf{√((Length)^2 + (Breadth)^2)}`

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