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F (x) = 2log (1/4x-5) +6 Find the Inverse f-1(x) = 120.52–3 + 20 f-1(x) = 4.30.53–6 +5 f-1(x) = 4.30.52–3 + 20 -6 = =

F (x) = 2log (1/4x-5) +6 Find the Inverse f-1(x) = 120.52–3 + 20 f-1(x) = 4.30.53–6 +5 f-1(x) = 4.30.52–3 + 20 -6 = =
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F (x) = 2log

(1/4x-5) +6
Find the Inverse

f-1(x) = 120.52–3 + 20
f-1(x) = 4.30.53–6 +5
f-1(x) = 4.30.52–3 + 20
-6
=
=

asked
User Jesan Fafon
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1 Answer

7 votes

Answer:

6 is the answer for the question

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User Aditya Giri
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