Question

By titration, it is found that 73.3 mL of 0.175 M NaOH(aq) is needed to neutralize 25.0 mL of HCl(aq). Calculate the concentration of the HCl solution.

Answer 1

0.5131M

Step-by-step explanation:

NaOH(aq) + HCl(aq) — NaCl(aq) + H20(l)

Mole ratio of acid to base 1:1

(Ca × Va)/ (Cb × Vb) = Na/Nb

(0.175 × 73.3)/ (Cb × 25)= 1/1

12.8275= 25 × Cb

Cb= 12.8275/25

= 0.5131M