Question

write an equation in slope intercept form for the line that passes through the point, and is perpendicular to the line y=-1/3x+9;(-6,-2)

Answer 1

Explanation:

y=-1/3x+9

This is written in the format y=mx+b, where m is the slope and b the y-intercept (the value of y when x=0).

Perpendicular lines have a slope that is the negative inverse of the slope of the reference line, in this case -(1/3). The new slope is 3. equation is:

y = 3x + b

To find b, enter the given point, (-6,-2) and solve for b:

y = 3x + b

-2 = 3(-6) + b

-2 = -18 + b

b = 16

The full equation is y=3x + 18