Answer:
45g
Step-by-step explanation:
first we will find out which is the limiting reactant (hope you know how to find it)
Cao is the limiting reactant
so
we will find the number of moles of cao which is 0.45 mol
as according to the equation cao and caco3 have ratios 1:1 so both will have the same no. of moles
then by multiplying 0.45mol by 100 (mr of caco3) we will get the mass of caco3 which is 45g