Question

When divide f(x)=ax³+bx²+cx+d by (x+3), the remainder is 4, then what is the remainder when divide 2f(x)-6 by (x+3)?​

Answer 1

• 2

Explanation:

When divide f(x)=ax³+bx²+cx+d by (x+3), the remainder is 4:

• f(x) = m*(x + 3) + 4, where m is the quotient

Then 2f(x) - 6 is:

• 2[m(x + 3) + 4] - 6 =
• 2m(x + 3) + 8 - 6 =
• 2m(x + 3) + 2

As we see the remainder is 2