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2cosAcosB = • cos(A + B) + cos(A - B) • sin(A - B) + tan(A + B)

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asked Jun 20, 2022 52.0k views

5 votes

2cosAcosB =

• cos(A + B) + cos(A - B)
• sin(A - B) + tan(A + B)

Mathematics
college

Bilal Shah asked

by Bilal Shah

7.9k points

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1 Answer

6 votes

Answer:

2cosAcosB = cos( A + B ) + cos( A - B )

Dark Cyber answered Jun 25, 2022

by Dark Cyber

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2cosAcosB = • cos(A + B) + cos(A - B) • sin(A - B) + tan(A + B)

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