Question

If cot of theta is the square root of 3, calculate (sin of theta)(cot of theta) - cos^2 of theta (in exact numbers)

Answer 1

\frac{\sqrt{3} }{2} - .75

Explanation:

cot Θ = Sqrt (3)

SinΘ = 1/2 CscΘ = 2

CosΘ = Sqrt3 / 2 SecΘ = 2Sqrt3 / 3

TanΘ = Sqrt3 / 3 CotΘ = Sqrt (3)

Cotangent is Adjacent over Opposite

Adjacent = Sqrt 3

Opposite = 1

That means the Hyp = 2 (Pythag Theorem)

Sin Θ * Cot Θ - CosΘ ² =

1/2 * Sqrt 3 - .75 = (Sqrt3 / 2) - .75

Sqrt3 / 2 - .75 is as far as I can get.