Question

A 65kg swimmer pushes off the pool wall and accelerates at 6m/s2. The friction experienced by the swimmer is 100n. What is the magnitude of the force that the swimmer applies on the wall?.

Answer 1

490 N

Step-by-step explanation:

Fnet = ma

= 65*6

= 390 N

Net force is applied force (Fapp) and friction force (Ff) in the opposite direction.

Fnet= Fapp - Ff

390=x-100

x=490N