asked 120k views
4 votes
Cosθ(tanθ + cotθ) =

• cscθ

• secθ

• cos^2θ

• 1

asked
User Pts
by
7.7k points

2 Answers

5 votes


\cos \theta(\tan \theta + \cot \theta)\\\\=\cos \theta \tan \theta + \cos \theta \cot \theta \\\\=\cos \theta \left ((\sin \theta)/(\cos \theta) \right)+ \cos \theta \left((\cos \theta)/(\sin \theta) \right)\\\\\\=\sin \theta + (\cos^2 \theta)/(\sin \theta)\\\\=(\sin^2 \theta + \cos^2 \theta)/(\sin \theta)\\\\=\frac 1{\sin \theta}\\\\=\csc \theta

answered
User Orit
by
8.4k points
5 votes

Answer:

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Explanation:

answered
User Ishara
by
7.9k points
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