Question

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Answer 1

`\huge\boxed{z=6;\ x=12.5}`

Explanation:

If two figures are similar, then corresponding sides are in proportion.

Therefore:

`(z)/(15)=(4)/(10)\qquad|\text{cross multiply}\\\\10z=(15)(4)\\\\10z=60\qquad|\text{divide both sides by 10}\\\\\boxed{z=6}`

`(x)/(5)=(10)/(4)\qquad|\text{cross multiply}\\\\4x=(5)(10)\\\\4x=50\qquad|\text{divide both sides by 4}\\\\x=(50)/(4)\\\\\boxed{x=12.5}`