Question

Given that TANꝊ= - 4/3 and Ꝋ is in quarednt II, find SIN 2Ꝋ

Answer 1

tan= -4/3

`tan^-1(-4/3)\\=53.13\\`

-4 is the opposite

-3 is the adjacent

`sin(-53.1301)*sin(-53.1301)\\(4)/(5) *(4)/(5)\\(16)/(25)=0.64`

Explanation:

We will find the angle

We will then use the angle to find the sin value and multiply them both to find the square.

I will suggest you keep to fractions will working.

Answer 2

Explanation: Theta = T. tanT = -4/3, T must be in second Quadrant. arctan(-4/3) = T.