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Prepare a mixture of 300 mL of 70% alcohol and 200 mL of 95% alcohol. What is the percentage strength of the final solution?

Prepare a mixture of 300 mL of 70% alcohol and 200 mL of 95% alcohol. What is the percentage strength of the final solution?
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Prepare a mixture of 300 mL of 70% alcohol and 200 mL of 95% alcohol. What is the percentage strength of the final solution?

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User Michael Brux
by
8.4k points

1 Answer

6 votes

Answer:

Explanation:

300(0.70) + 200(0.95) = (300 + 200)x

400 = 500x

x = 0.80

80%

answered
User Tameca
by
8.4k points
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