Answer:
4
Explanation:
Review
To evaluate the expression, lets use BODMAS. Before we get to the solving part, lets revise BODMAS.
=> B in BODMAS is brackets. This means that whatever operations are inside a bracket, we must solve that first.
=> O in BODMAS is Orders. The O is used very rarely, there is a possibility that there is no powers, exponents.
=> D in BODMAS is Division. This means that whatever division is occurring in the expression must be done first (Unless if there is a bracket).
=> M in BODMAS is Multiplication. This means that whatever multiplication is occurring in the expression must be done next.
=> A in BODMAS is Addition. This means that whatever addition is occurring in the expression must be done then.
=> S in BODMAS is Subtraction. This means that whatever subtraction is occurring in the expression must be done last.
Solution:
Now, lets get to the point. We need to find the expression '2−[(2+10(−1)÷2)+1]'. Using the help of BODMAS, we can solve it.
Step 1: Simplify the innermost bracket.
2 − [( 2 + 10(−1)÷2)+1]
=> 2-[(2-10÷2)+1]
Note: Since in the innermost bracket there is no operation, we can open the innermost bracket and get along with the second inner bracket.
Step 2: Simplify the second inner bracket.
=> 2 - [(2 - 10 ÷ 2) + 1]
=> 2 - [(2 - 5) + 1]
=> 2 - [(-3) + 1]
=> 2 - [-3 + 1]
Step 3: Simplify the third inner bracket.
=> 2 - [-3 + 1]
=> 2 + 2
Step 4: Solve.
=> 2 + 2
=> 4
Final Answer.
Therefore, 4 is our answer after working on this problem.