Question

1.

Identify the minimum value of the function y = 3x^2 − 12x + 10.

A. −2

B. 10

C. 46

D. 2

Answer 1

A

Explanation:

The minimum value is the y- coordinate of the vertex

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x = -
`(b)/(2a)`

y = 3x² - 12x + 10 ← is in standard form

with a = 3 and b = - 12 , then

x = -
`(-12)/(6)` = 2

Substitute x = 2 into the function for corresponding y- coordinate

y = 3(2)² - 12(2) + 10 = 3(4) - 24 + 10 = 12 - 24 + 10 = - 2

Then minimum value of the function is - 2

Answer 2

-2

Explanation: