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C is the midpoint of chord AB and D is the midpoint of arc AB.Given that AB=36 unit and CD=6 unit then What is the radius of circle?

C is the midpoint of chord AB and D is the midpoint of arc AB.Given that AB=36 unit and CD=6 unit then What is the radius of circle?
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C is the midpoint of chord AB and D is the midpoint of arc AB.Given that AB=36 unit and CD=6 unit then What is the radius of circle?

asked
User NNsr
by
8.5k points

1 Answer

6 votes

Answer:

By power of a point, AC⋅CB=DC⋅CE. That is, 12⋅12=6⋅(2R–6).

Then, R=15.

answered
User Kuba Jagoda
by
8.9k points
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