Question

What is its time interval between the release of the ball and the time it reaches its maximum height? Its initial vertical speed is 9 m/s and the acceleration of gravity is 9.8 m/s 2 . Neglect air resistance.

Answer 1

The time to reach max height is h = 1/2 g t^2

The time to fall is the same as that for an equivalent rise

m g h = 1/2 m v^2 KE vs PE

Here: (Vf - VI) / g = t = -9 / -9.8 = .92 s