Question

A line passes through the point (10,-5) and a slope of -3/2

Write an equation in slope-intercept form for this line.

Answer 1

y = -3/2x + 10

Explanation:

The slope = -3/2

Using the slope = -3/2 and the point (10, -5) substitute into y = mx + b and solve for "b"

y = mx + b

-5 = -3/2(10) + b -3/2 · 10 = -30/2 = -15

-5 = -15 + b

-5 + 15 = b

10 = b

The equation of the line is y = -3/2x + 10