Question

What are the zeros of the function
f(x)=x^2+2x-8

Answer 1

-4, 2 (-4,0) (2,0)

Explanation:

factoring in binomials

`(x+4)(x-2)=x^(2) +2x-8`

The zeros:

`x+4=0\\x=0-4\\x_(1) =-4`

`x-2=0\\x=0+2\\x_(2) =2`

I hope this help you