Question

The coordinates of three vertices of a square abcd are A (-2.5,1.5) B (-2.5,-3) and C (2,1.5) When point D is placed on this square, what willl be the perimeter of the square be? PLEASE HELP ASAP

Answer 1

18

Explanation:

We know in a square ABCD, AB=CD=BC=AD

so the perimeter of ABCD will be 4AB.

now find the AB:

A(—5/2 , 3/2) so x1=—5/2 , y1=3/2

B(—5/2 , —3) so x2=—5/2 , y2= —3

AB=

`\sqrt{ {(x1 - x2)}^(2) + {(y1 - y2)}^(2) } = \sqrt{ {(0)}^(2) + {4.5}^(2) } = 4.5`

Now, AB=4.5 and 4AB=18

The perimeter is 18