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How many moles of NO₂ would be required to produce 5.73 moles of HNO₃ in the presence of excess water in the following chemical reaction? 3 NO₂(g) + H₂O (l) → 2 HNO₃(g) + NO(g)<…

How many moles of NO₂ would be required to produce 5.73 moles of HNO₃ in the presence of excess water in the following chemical reaction? 3 NO₂(g) + H₂O (l) → 2 HNO₃(g) + NO(g)<…
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How many moles of NO₂ would be required to produce 5.73 moles of HNO₃ in the presence of excess water in the following chemical reaction?

3 NO₂(g) + H₂O (l) → 2 HNO₃(g) + NO(g)

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User Dombesz
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1 Answer

6 votes

Answer:

8.595 mol NO2

Step-by-step explanation:

5.73 mol HNO3 *
((3 mol NO2)/(2 mol HNO3)) = 8.595 mol NO2

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User Matthiasunt
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8.3k points
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